How find future month and year in python

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http://labix.org/python-dateutil#head-ba5ffd4df8111d1b83fc194b97ebecf837add454

today + relativedelta(months=1)


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  def next_month(self, date):
      month = date.month+1
      year = date.year
      if month > 12:
          month = 1
          year = date.year+1
      return datetime.datetime(year, month, 1)


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today = datetime.date.today()
      next_first_date = today + datetime.timedelta(today.day)
      next_second_date = next_first_date + datetime.timedelta(today.day)
      next_third_date = next_second_date + datetime.timedelta(today.day)
      print "third", next_third_date
      print "second", next_second_date
      print "next_first_date", next_first_date

      next_first_month = next_first_date.month
      next_first_year = next_first_date.year
      next_first_month_name = next_first_date.strftime("%b")

      next_second_month = next_second_date.month
      next_second_year = next_second_date.year
      next_second_month_name = next_second_date.strftime("%b")

      next_third_month = next_third_date.month
      next_third_year = next_third_date.year
      next_third_month_name = next_third_date.strftime("%b")